how to disable the picture

Hi, every time I run the following code, a figure is generated. How can I disable it?
Thanks.
a0 = 0.05; a1 = 0.1; b1 = 0.85;
nu = randn(2300,1);
epsi = zeros(2300,1);
h = zeros(2300,1);
for i=2: 2300
h(i) = a0 + a1 * epsi(i-1)^2 + b1 * h(i-1) ;
epsi(i) = nu(i) * sqrt(h(i));
end
yt = zeros(2300,1);
for i=1: 2300
yt(i) = epsi(i)*epsi(i);
end
order = 15;
m = arx(yt, order);

7 Kommentare

Image Analyst
Image Analyst am 18 Feb. 2013
Bearbeitet: Image Analyst am 18 Feb. 2013
I ran it up through the arx() function and it produced no figure. It must get produced in arx(). What is that function? Is it in some toolbox that you forgot to list in the Products below, like the MATLAB coder which you listed in the Tags?
dav
dav am 18 Feb. 2013
Bearbeitet: Image Analyst am 19 Feb. 2013
Sorry a part of the code was missing in my first question
here's the code again.. It is the corr function of the residuals
a0 = 0.05;
a1 = 0.1;
b1 = 0.85;
nu = randn(2300,1);
epsi = zeros(2300,1);
h = zeros(2300,1);
for i=2: 2300
h(i) = a0 + a1 * epsi(i-1)^2 + b1 * h(i-1) ;
epsi(i) = nu(i) * sqrt(h(i));
end
yt1 = zeros(2300,1);
for i = 1 : 2300
yt1(i) = epsi(i)*epsi(i);
end
yt=yt1(1301:2300);
order = 15;
m = arx(yt1, order);
r = resid([yt1(1:order);yt1], m);
r = r(order+1:end);
Walter Roberson
Walter Roberson am 19 Feb. 2013
I do not understand what this question has to do with the Mathworks product that converts MATLAB code to C or C++ code? You tagged this with "MATLAB Coder" ?
Image Analyst
Image Analyst am 19 Feb. 2013
And I still don't get a spurious figure, or any figure at all. It runs up until the call to arx() and then bombs. Again, what toolbox is arx() in? I guess it doesn't matter though since whatever toolbox it's in, I don't have it, but others who might want to help you might want to know this so they don't waste their time too. Or is arx() some custom m-file you wrote?
Walter Roberson
Walter Roberson am 19 Feb. 2013
arx() appears to be in Systems Identification but that does not appear to me to plot anything.
dav
dav am 19 Feb. 2013
I am sorry its in the system identification tool box
Walter Roberson
Walter Roberson am 19 Feb. 2013
Have you tried using the debugger and stepping through the code to find out which command is generating the plot ?

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Antworten (2)

Youssef  Khmou
Youssef Khmou am 19 Feb. 2013

1 Stimme

hi,
your code does not produce any figure,
but if you want, you can add the following at the end of your code :
close;
Rajiv Singh
Rajiv Singh am 19 Feb. 2013

1 Stimme

It is the RESID command that is bringing up the plot. It belongs to System Identification Toolbox. To make it work as documented (no figures when called with output arguments), use an IDDATA object to represent the data, as in:
r = resid(iddata([yt1(1:order);yt1]), m);
Calling RESID with double vector representing data is supported for backward compatibility. However, in this mode, the plot also gets shown since this was the behavior in the past before IDDATA object was introduced (I believe in ver 5).

1 Kommentar

dav
dav am 21 Feb. 2013
Bearbeitet: dav am 21 Feb. 2013
thnks. but the problem is that now I dont get the residuals either... can u fix that please?
I need to get the residuals in to a vector (r). But when i type r at the command prompt I dont see the residuals.
thanks

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dav
am 18 Feb. 2013

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