Plotting Multivariable x, y, and z for a data set

9 Ansichten (letzte 30 Tage)
SugerCodeCude
SugerCodeCude am 5 Okt. 2020
Kommentiert: Star Strider am 6 Okt. 2020
I have made a 3d multivatiable gird that is, x, y, and z
grid_x = 1:1:10;
grid_y = 1:1:10;
grid_z = 1:1:10;
then in a 3 loop (3d multivariable) I calculate values for a give equation and save is it in a variable called values(:,:). the multivariable values has points between 1:10 random numbers
Now I have used
[X,Y] = meshgrid(grid_x,grid_y);
Z = griddata(grid_x,grid_y,grid_z,X,Y);
however Z is not where the values are, when I call
surf(X,Y,Z)
I get a empty plot in 3d, here is where I am not understand how to call in the data points which is called values, even when I did
surf(X,Y,Z,values(:,:))
I get a empty plot in 3d.
Please tell me to clarify if needed.

Akzeptierte Antwort

Star Strider
Star Strider am 5 Okt. 2020
The problem is with your choice of coordinates.
When I ran your code, it threw:
Warning: The underlying triangulation is empty - the points may be collinear.
> In griddata>useScatteredInterp (line 183)
and ‘Z’ was empty.
Creating random values instead resulted in the sort of result you want:
grid_x = rand(1,50);
grid_y = rand(1,50);
grid_z = randn(size(grid_x));
[X,Y] = meshgrid(0:0.01:1, 0:0.01:1);
Z = griddata(grid_x,grid_y,grid_z,X,Y);
figure
surf(X,Y,Z)
grid on
.
  13 Kommentare
SugerCodeCude
SugerCodeCude am 6 Okt. 2020
Thank you so mch, this back and forth help me understand the issues I was having. Thank you again!
Star Strider
Star Strider am 6 Okt. 2020
As always, my pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by