create a variable based on timetable's date period

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Sehoon Chang
Sehoon Chang am 1 Okt. 2020
Kommentiert: Star Strider am 1 Okt. 2020
Hello dear advisors.
i wish to create a new variable (HP) for my timetable (TT) which datetime covers for multiple years.
For the periods in between 01.October till 30.April of each year available within the timetable, each timestamp shall get the value of 1 as a variable HP.
And as for the rest (01.May till 30.September), each remaining timestamps shall get the value of 0 as a variable of HP.
for example:
thanks!

Akzeptierte Antwort

Star Strider
Star Strider am 1 Okt. 2020
Try this:
DT = (datetime([2017 01 01]):caldays(1):datetime([2020 01 01])).'; % Create Dates
HP = ones(size(DT)); % Create ‘HP’
TT = timetable(DT,HP); % Create ‘timetable’
TF = [(TT.DT(day(TT.DT)==1 & month(TT.DT)==5)) (TT.DT(day(TT.DT)==30 & month(TT.DT)==9))]; % Starting & Ending Dates For All Years
for k = 1:size(TF,1)
TT.HP(TF(k,1) : TF(k,2),:) = 0; % Loop Through Years
end
Check = [TT(115:125,:); TT(270:280,:)]; % Check That It Works! (Delete Later)
CheckPlus1Yr = [TT((115:125)+365,:); TT((270:280)+365,:)]; % Check That It Works! (Delete Later)
Use the ‘TF’ matrix and the loop with your own timetable.
I called my datetime variable ‘DT’ to avoid using ‘datetime’ as a variable name.
The ‘Check’ lines show parts of the timetable demonstrating that this approach works. They are not otherwise a necessary part of the code, so delete them later.
  2 Kommentare
Sehoon Chang
Sehoon Chang am 1 Okt. 2020
thank you Star Strider,
you advices are great help!
Star Strider
Star Strider am 1 Okt. 2020
As always, my pleasure!
Thank you!

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Weitere Antworten (1)

Steven Lord
Steven Lord am 1 Okt. 2020
Bearbeitet: Steven Lord am 1 Okt. 2020
Using the sample timetable Star Strider created:
DT = (datetime([2017 01 01]):caldays(1):datetime([2020 01 01])).';
HP = ones(size(DT));
TT = timetable(DT,HP);
Get the list of months for each row in the timetable:
M = month(TT.DT);
Determine which months are between May (5th month) and September (9th month) inclusive.
isInRangeFor0 = ismember(M, 5:9);
Create the new variable. Since isInRangeFor0 is true when we want the new variable to have value 0 and vice versa, we can just negate that variable.
TT.newvar = ~isInRangeFor0;
  1 Kommentar
Star Strider
Star Strider am 1 Okt. 2020
That’s definitely an interesting alternative.
Using ismember for the months didn’t occur to me. I’ll definitely keep that in mind!

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