Hello
I have a array of numbers but the first cell is always a string like below. Is there way that I put ''0" instead of "theta\phi[rad]"? Then, I can do analysis :)
theta\phi[rad] 0 0.01 0.02
0 -0.15 -0.17 -0.14
0.2 0.19 -0.13 -0.11

 Akzeptierte Antwort

madhan ravi
madhan ravi am 25 Sep. 2020
Bearbeitet: madhan ravi am 25 Sep. 2020

1 Stimme

cell_array(cellfun(@isstring, cell_array)) = {0}

7 Kommentare

Masoud Taleb
Masoud Taleb am 25 Sep. 2020
Thanks for the reponse. But it gives error! Should I give a value for cell_array?
Unrecognized function or variable 'cell_array'.
Error in Untitled (line 9)
cell_array(cellfun(@isstring, cell_array)) = {0}
madhan ravi
madhan ravi am 25 Sep. 2020
Bearbeitet: madhan ravi am 25 Sep. 2020
Lol , cell_array is your values contained in a cell. It was just for illustration purposes.
If you just want the first cell to turn to zero. Then:
cell_array{1} = 0
Masoud Taleb
Masoud Taleb am 25 Sep. 2020
Unfortunately, this one does not work as well. It removes whole line!
madhan ravi
madhan ravi am 25 Sep. 2020
Bearbeitet: madhan ravi am 25 Sep. 2020
What??! Upload your cell data as .mat file.
>> cell_array
cell_array =
3×4 cell array
{["theta\phi[rad]"]} {[ 0]} {[ 0.0100]} {[ 0.0200]}
{[ 0]} {[-0.1500]} {[-0.1700]} {[-0.1400]}
{[ 0.2000]} {[ 0.1900]} {[-0.1300]} {[-0.1100]}
>> cell_array{1} = 0
cell_array =
3×4 cell array
{[ 0]} {[ 0]} {[ 0.0100]} {[ 0.0200]}
{[ 0]} {[-0.1500]} {[-0.1700]} {[-0.1400]}
{[0.2000]} {[ 0.1900]} {[-0.1300]} {[-0.1100]}
>>
I have no idea about what you're talking about.
OK, I do not know why your solution did not work for me but following one fixed the problem:
id = find(A{1}==',');
A{1}(1:id(1)-1) = '0';
madhan ravi
madhan ravi am 25 Sep. 2020
Obviously, the example you showed in your code and your last comment don’t contain the same data.
Masoud Taleb
Masoud Taleb am 25 Sep. 2020
I tried to simplify the example as my data file and main codes are very big and complicated to be uploaded. Meanwhile, it is possible that something was interfering it. Anyway, thanks for your reply and help :)

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