if statements inside a function file and the function called by a for loop
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hi every body im new in matlab and i have this script
clear all
format long
k=100;
dx=1;
x=zeros(k,1);
y=zeros(k,1);
x(1)=1;
for n=2:k;
x(n)=x(n-1)+dx;
[ y ] = test( x );
end
tb=[x(1:k) y(1:k)]
and this function file
function [ y ] = test( x )
if x<25
y=x*2;
elseif x>25
y=x*10;
else
y=x*1000;
end
when i run it just the
else
y=x*1000;
end
part is evaluated, and i want all the x(n) be evaluated in the correct if.
what im doing wrong?
1 Kommentar
Walter Roberson
am 25 Jan. 2013
Why does your program start with "clear all" ??
Antworten (3)
Walter Roberson
am 25 Jan. 2013
An evaluated expression is true when the result is nonempty and contains all nonzero elements (logical or real numeric). Otherwise, the expression is false.
What are you testing? x<25.
How big is x?
Does x<25 result in all non-zero elements?
Roger Stafford
am 25 Jan. 2013
Bearbeitet: Roger Stafford
am 25 Jan. 2013
0 Stimmen
When you write "y=test(x)" rather than "y=test(x(n))" or "y=test(x(n+!))", you are passing 'test' an x vector with 100 elements in it and the resulting y will also have 100 elements. At the 'if' and 'elseif' points in 'test' each would always require that the given condition hold for all hundred cases of x and that is never true. Hence only the 'else' part is ever executed. Look up the documentation on 'if' and 'elseif'.
2 Kommentare
MEXICO
am 25 Jan. 2013
Walter Roberson
am 25 Jan. 2013
Yes, x(n). And assign the result to y(n)
MEXICO
am 25 Jan. 2013
0 Stimmen
1 Kommentar
Walter Roberson
am 25 Jan. 2013
Please look in the MATLAB documentation for information about logical indexing.
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