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While loop keep running (logical with vector )

1 Ansicht (letzte 30 Tage)
Ali Tawfik
Ali Tawfik am 10 Sep. 2020
Kommentiert: Ameer Hamza am 10 Sep. 2020
Hi all,
My while loop running without stopping, I wanna it run until reach to logical function of a equal or smaller than 10. which should be any two numbers a=[6 3] or a=[6 6]
thanks,
clearvars;
clc;
a=[0 0];
while all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
  2 Kommentare
Ameer Hamza
Ameer Hamza am 10 Sep. 2020
Can you describe the condition more clearly?
Ali Tawfik
Ali Tawfik am 10 Sep. 2020
Hi Ameer,
Thanks for your prompt reply.
Actually I am trying to run the loop until the following condition meet:
(a) is smaller or equal to 6.

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Akzeptierte Antwort

Ameer Hamza
Ameer Hamza am 10 Sep. 2020
Bearbeitet: Ameer Hamza am 10 Sep. 2020
Check this
clc;
a=[inf inf]; % start with all elemets > 6
while ~all(a <= 6)
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end
  4 Kommentare
Ali Tawfik
Ali Tawfik am 10 Sep. 2020
@ Ameer, thanks Now its working... Would you mind having a look into my new question as I have been stucked for a while !!! and need any help !
Ameer Hamza
Ameer Hamza am 10 Sep. 2020
I am glad to be of help! The other question seems to be a bit complicated to debug, but the main error is in the use of all() function. As you can see in my code, the comparison should be inside the all() function, not outside.
For example, instead of
all(x) > 1
you should write
all(x > 1)

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Weitere Antworten (1)

BOB MATHEW SYJI
BOB MATHEW SYJI am 10 Sep. 2020
I think replacing while with if solves the problem
clearvars;
clc;
a=[0 0];
if all(a)<=6
z=[6 10 8 9 22 3 6];
for i=1:2
z(i)=z(randi(end));
a(i)=z(i)+1
end
end

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