If statement with == not working with vector

So I'm making a code that's basically Hangman where the user has to guess the letters in a word that's already been decided. I did that by making each word into a vector.

The if/else statement shown below is where, if the letter the user enters matches a letter in the word, it prints "correct" but if it doesn't, it prints "incorrect". My issue is that even if the user's guess matches one of the letter, (and it prints "correct"), it also prints incorrect for every other letter.

if guess==word(k)
    disp ('Correct!')
else
    disp ('Incorrect')
end

I tried writing it as two seperate if statements but that didn't change anything.

if guess==word(k)
    disp ('Correct!')
end

if all(guess~=word(k))
    disp ('Incorrect')
end

I also tried the two if statemnts with break at the end of each but that jsut made it print incorrect every time.

Anyone have any idea how to fix this? I'd really appreciate it!

EDIT:

I've added my code as a whole so you can see what I'm trying to do, in case that makes things clearer:

disp ('Lets Play Hangman (the theme is colours)')
disp ('   ')

r=randi([1,4],1);

if r==1
    word='RED';
elseif r==2
    word='ORANGE';
elseif r==3
    word='YELLOW';
elseif r==4
    word='GREEN';
end

len_word= length(word);

fprintf ('Your letter is %d letters long \n', len_word)

attempts_left=9;

for k=1:len_word
   shadow_array(k) = '*';
end

for max_guesses=[1:1:9]
    guess=input('Enter a letter: ', 's');
    guess=upper(guess);
    
    for k=[1:1:len_word]
        word(k);

% PROBLEM AREA
        if guess==word(k)
            disp ('Correct!')
            shadow_array(k)=num2str(word(k));
        else
           disp ('Incorrect')
           attempts_left=attempts_left-1
        end
% issue is that it else runs for every letter that ~=k (even if one letter is correct)
        
    end
    
    disp (shadow_array)
  
    if all (shadow_array~='*')
        disp ('\nYOU WON!\n')
        break
    end  
end

disp ('GAME OVER')

Answer 1

[Star Strider]

To compare strings, use strcmp (or the case-insensitive version, strcmpi, linked to in that page).

Depending on what you want to do, another option is contains.

EDIT —

Some contains examples:

word = 'shark';
guess1 = 'k';
guess2 = 'q';

test1 = contains(word, guess1)
test2 = contains(word, guess2)

.

[Kalista Hall]

I tried using contains as shown below but when I did that, if the word does contain the letter, it prints correct 5 (or however many letters are in the word) times and the complete word and jumps straight to the end of the code.

 is_it_there=contains(word,guess);
 
        if   is_it_there==1
            disp ('Correct!')
        else
           disp ('Incorrect')
        end

I've edited my question to add in the code as a whole in case that clarifies anything.

[Star Strider]

I do not see that in the other code you posted.

It should not jump to the end of the code. It should instead continue in whatever loop you put it, so only when the conditions for the loop are satisfied should the loop terminate and go to the end of the code. (It would seem that it has to be in the ‘max_guesses’ loop somewhere. I leave it to you to determine where that is.)

Also, experiment with something along the lines of:

if any(it_is_there)

since depending on the word, there could be more than one match, for example ‘YELLOW’ and ‘GREEN’. It is also not necessary to test that it is equal to 1, simply that it is true, and the any function will detect that.