Plot 3D implicit function
Ältere Kommentare anzeigen
Dear all,
I want to plot the following function C(x,y,z,t) with C and t being fixed, so we can get the implicit function of z in terms of x and y.

The plot should look like with C and t are known. x, y in the interval of [0 15].

I write a code like this, but it gives an empty figure, no geometry is shown in the figure. Could anyone help me identify the error or give me some other solutions to produce such plots
u0=0.5; v0=u0; w0= -1;
x0=5; y0=x0; z0=x0; % initial injection position
D0=0.1;
U=sqrt(u0^2+v0^2+w0^2);
lim=10;
N=200;
c0=0.01;
t=0.1;
f=@(x,y,z) 1./(8*abs(u0*v0*w0).*sqrt((pi*D0*t).^3.*x.*y.*z.*x0.*y0.*z0)).*(x./x0).^(-2*D0*u0).*(y./y0).^(-2*D0*v0).*(z./z0).^(-2*D0*w0)...
.*exp(4.*D0.*t./((1/u0^2.*(log(x./x0)).^2+1/v0^2.*(log(y./y0)).^2+1/w0^2.*(log(z./z0)).^2)+(3+D0.^2.*U.^2).*t.^2))-c0;
interval = [0 10 0 10 0 10];
fimplicit3(f);
Antworten (1)
Alan Stevens
am 23 Aug. 2020
0 Stimmen
This is because your function is never zero with the constants you've used. Try setting c0 = 1.
1 Kommentar
Yubiao Sun
am 24 Aug. 2020
Kategorien
Mehr zu 2-D and 3-D Plots finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!