matrix addition different dimension using for loops.

3 Ansichten (letzte 30 Tage)
Hi,
I am trying to do matrix addition of 2*4 to fit in 4*4 matrix. I am using for loops to get me familiarize with loops so that i can use it for image matrix manupulation. But with my code my output is 2*4 instead of 4*4.. could someone explain me the concept or the logic i am lacking here ..
a = [11:14; 15:18];
b = [3 2 3 1; 2 1 1 1;1 3 3 2; 2 1 1 3];
for i = 0
for j = 0
for x = 1:2
for y = 1:4
c(i+x,j+y) =b(i+x,j+y)+a(x+i,y+j);
end
end
end
end
  2 Kommentare
Walter Roberson
Walter Roberson am 16 Aug. 2020
If the first matrix were
1 2 3 4
5 6 7 8
and the second matrix was all zero, then what would you want the result of the addition to be ?
Malini Bakthavatchalam
Malini Bakthavatchalam am 16 Aug. 2020
1 2 3 4
5 6 7 8
1 2 3 4
5 6 7 8
This would be my resultant matrix

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 16 Aug. 2020
%this code will fail if a or b is empty, or if one size is not an exact multiple of the other
asz = size(a);
bsz = size(b);
maxsz = max(asz,bsz);
arep = maxsz ./ asz;
brep = maxsz ./ bsz;
ar = repmat(a, arep);
br = repmat(b, brep);
c = ar + br;
That is, create new matrices that contain the old matrices copied as many times as needed.
  3 Kommentare
Walter Roberson
Walter Roberson am 16 Aug. 2020
Bearbeitet: Walter Roberson am 16 Aug. 2020
ar = repmat(a, arep);
can be replaced with
[arows, acols, apanes] = size(a);
ar = zeros(arows*arep(1), acols*arep(2), apanes, class(a));
for J = 1 : arep(1)
arows = (J-1)*arows+1 : J*arows;
for K = 1 : arep(2)
acols = (K-1)*acols+1 : K*acols;
ar(arows, acols, :) = a;
end
end
Walter Roberson
Walter Roberson am 16 Aug. 2020
I fixed a typing mistake in setting the class of ar

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by