How to Use arrayfun with a Multivariate Function of n Variables?

3 Ansichten (letzte 30 Tage)
Kareem Elgindy
Kareem Elgindy am 3 Aug. 2020
Kommentiert: Arthur Roué am 4 Aug. 2020
Suppose f(X) is a function of a vector X = [x1, x2, ..., xn]. How to evaluate the function at a certain range of values, say y1, y2, ..., ym, for the variable xi while keeping all other variables fixed?
To make it simple: Say x1, ..., x59, x61, ..., x100 = 10, and we want to evaluate the function for three different values for x60, say at 1.5, -3, and 12. Can we do this without for loops?

Antworten (2)

Arthur Roué
Arthur Roué am 3 Aug. 2020
Bearbeitet: Arthur Roué am 3 Aug. 2020
arrayfun is generally not faste than a for loop, becaut it has an internal for loop. read this for more details : https://fr.mathworks.com/matlabcentral/answers/324130-is-arrayfun-faster-much-more-than-for-loop
So I reccomend something like
X = [x1 .. xn];
x60 = [1.5, -3, 12];
Y = NaN(1, numel(x60)); % Pre-allocation (not required for small vectors)
for idx = 1:numel(x60)
X(60) = x60(idx)
Y(idx) = yourFun(X)
end
  4 Kommentare
Kareem Elgindy
Kareem Elgindy am 3 Aug. 2020
OK. But how to calculate the 3xN matrix quickly then. Can we do it without for loops?
Arthur Roué
Arthur Roué am 4 Aug. 2020
Can you share the code of your function ?

Melden Sie sich an, um zu kommentieren.


Souradeep Mukhopadhyay
Souradeep Mukhopadhyay am 3 Aug. 2020
You should make 3 different X arrays here X1, X2, X3 and then pass the 3 arrays in function 3 times to compute y 3 times.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Produkte


Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by