Doubt in the specific line
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
could you please explain the following code?
k = zeros(img_h, img_w, 4);
k(:,:,1) = (fxx./((1 + fx.^2).^(3/2))).*fvr; % hor
k(:,:,2) = (fyy./((1 + fy.^2).^(3/2))).*fvr; % ver
k(:,:,3) = (f11./((1 + f1.^2).^(3/2))).*fvr; % \
k(:,:,4) = (f22./((1 + f2.^2).^(3/2))).*fvr; % /
Wr = 0;
bla = k(:,:,1) > 0;
for y=1:img_h
for x=1:img_w
if(bla(y,x)) %%% I cant understand (bla(y,x))
Wr = Wr + 1;
end
0 Kommentare
Akzeptierte Antwort
KSSV
am 24 Jul. 2020
Bearbeitet: KSSV
am 24 Jul. 2020
It is bad to ask such questions......asking to explain a specific line or a code. You have code in hand, play around with that. Print the values, run the code in debug and you can make yourself clear with the code.
bla = k(:,:,1) > 0;
In the above case bla is a logical matrix. It will have 0, and 1's. 0 where the condition >0 is not met and 1's where the condition > 0 is met.
if(bla(y,x))
In the above line a if condition is used, the conditon is met or if is executed if bla(x,y) is 1 or the if contion is not met.
0 Kommentare
Weitere Antworten (1)
Walter Roberson
am 24 Jul. 2020
The code
Wr = 0;
bla = k(:,:,1) > 0;
for y=1:img_h
for x=1:img_w
if(bla(y,x)) %%% I cant understand (bla(y,x))
Wr = Wr + 1;
end
end
end
can be entirely replaced with
Wr = nnz(k(:,:,1) > 0);
You are just counting the number of places that k(:,:,1) is true.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!