timer and counter function query using loops
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clc;
clear;
close all;
state = 0;
sequance = 0;
previous_state = 0;
for n = 0 : 15
time = n ;
p = 1;
input = int32(randi([0, 1], [1, p]));
comparison = isequal(input,previous_state);
previous_state = input;
if comparison == 0
state = state + 1;
sequance = 0;
else
%for zz = 0:10
sequance = sequance + 1;
%if sequance >= 2
time = time + (2^sequance/1000);
% end
%disp(state);
end
fprintf('%f %f %f %f\n',time,input,state,sequance);
end
0.000000 1.000000 1.000000 0.000000
1.000000 0.000000 2.000000 0.000000
2.002000 0.000000 2.000000 1.000000
3.004000 0.000000 2.000000 2.000000
4.008000 0.000000 2.000000 3.000000
5.016000 0.000000 2.000000 4.000000
6.000000 1.000000 3.000000 0.000000
7.002000 1.000000 3.000000 1.000000
8.000000 0.000000 4.000000 0.000000
9.002000 0.000000 4.000000 1.000000
10.000000 1.000000 5.000000 0.000000
11.002000 1.000000 5.000000 1.000000
12.004000 1.000000 5.000000 2.000000
13.008000 1.000000 5.000000 3.000000
14.016000 1.000000 5.000000 4.000000
15.000000 0.000000 6.000000 0.000000
Here, in my program the output in timer is incresing 0.004 msec. after 1 sec. but I want to incerase in particual at same sec. and print at same time.
Please help me, Thank you in advance
1 Kommentar
per isakson
am 1 Aug. 2020
"but I want to incerase in particual at same sec. and print at same time." I don't get what you want. Show an example!
"timer is incresing 0.004 msec" I would say that accourding to your code it's increasing by
( 2^sequance - 2^(sequance-1) )/1000
where
sequance = ( 1, 2, 3, ... )
during sequences when comparison==true which is what your output shows
Antworten (1)
Walter Roberson
am 17 Jul. 2020
I could not figure out your rules based upon your desired output. Here is one approximation that you could adapt further.
state = 0;
sequance = 0;
previous_state = 0;
prob = 0.1;
time = 1;
for n = 0 : 15
p = 1;
%input = int32(randi([0, 1], [1, p]));
input = int32(xor(previous_state, rand() < prob));
comparison = isequal(input,previous_state);
previous_state = input;
if comparison == 0
state = state + 1;
sequance = 0;
newtime = max(ceil(time), time+1);
else
%for zz = 0:10
sequance = sequance + 1;
if sequance > 9
newtime = time + 1;
else
newtime = time + state/100 + (2^sequance/1000);
end
% end
%disp(state);
end
fprintf('%10g %10g %10g %10g %10g\n',time,input,state,sequance,comparison);
time = newtime;
end
fprintf('\n');
1 Kommentar
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