Remove leading zeros from dates strings
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Santiago Costantino
am 16 Jul. 2020
Kommentiert: Santiago Costantino
am 17 Jul. 2020
Hello
I need to find the number of times a set of dates is included in a large text file. The problem is that the text file does not use leading zeros for months and days.
My code should look something like this:
myText=fileread('largeFile.txt');
dayOne=datetime('06/05/20','InputFormat','MM/dd/yy')
for it=1:10
numberOfTimes(it)=size(regexp(myText, datestr(dayOne+days(it), 'mm/dd/yy')), 2);
end
Thanks
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Akzeptierte Antwort
jonas
am 16 Jul. 2020
You can use histogram() to count occurences, either with datetime or categoricals as input.
dates = datetime(2010,1,12) + rand(1000,1)*days(365);
% with categoricals
dates_cell = cellstr(datestr(dates,'mm/dd/yy'));
dates_cat = categorical(dates_cell);
H = histogram(dates_cat)
3 Kommentare
Walter Roberson
am 17 Jul. 2020
You could use mm and then use regexp to strip out leading 0. But it hardly seems worth it considering that datetime() can handle the situation
dates = datetime(2010,1,12) + rand(10,1)*days(365);
dates.Format = 'M/d/yy';
dates_cat = categorical(cellstr(dates));
histogram(dates_cat);
Weitere Antworten (1)
Steven Lord
am 16 Jul. 2020
Use M instead of MM and d instead of dd in the input format. According to the description of the Format property on the documentation page (which is referenced in the documentation for 'InputFormat'), M handles "Month, numerical using one or two digits" as opposed to MM which handles "Month, numerical using two digits".
>> datetime('07-16-2020', 'InputFormat', 'M-dd-yyyy')
ans =
datetime
16-Jul-2020
>> datetime('7-16-2020', 'InputFormat', 'M-dd-yyyy')
ans =
datetime
16-Jul-2020
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