Obtaining the standard normal z score

Is there an easy way to obtain the standard normal z score with an upper tail probability of 0.05/2 or any number at hand

Answer 1

[Star Strider]

Try this:

z = norminv(1-0.05/2)

producing:

z =
     1.9600   

Without the Statistics and Machine Learning Toolbox:

CV = @(alpha) -sqrt(2) * erfcinv(2*alpha);    % Equivalent to ‘norminv’
z = CV(1-0.05/2)

producing the same result.

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