Dynamic Matrices in Matlab
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Hi!
Yesterday, I had a very similar question, now I want something a bit more advanced. So I have coded already:
data = [234,3,8;457,5,7;611,7,3;234,9,12]
ID = data(:,1);
X = data(:,2);
U = unique(ID)
data(U(i) == data(:,1),3)
display data
Now I want to create a matrix, where the first column would be the first column of the data matrix above (i.e. "id"). And all the following collumns would then store the values in the third column of data belonging to this id. So it would look like:
[234, 8,12; 457, 7,0; --- ]
But, obviously, I could not set the dimensions of this matrix from the beginning on, the number of columns would have to be dynamical. Is that possible?
Thanks
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Antworten (2)
Andrei Bobrov
am 13 Dez. 2012
Bearbeitet: Andrei Bobrov
am 13 Dez. 2012
[a,b,c] = unique(data(:,1));
d = accumarray(c,data(:,3),[],@(x){sort(x)});
n = cellfun(@numel,d);
m = numel(a);
out = [a, zeros(m,max(n))];
for j1 = 1:m
out(j1,2:n(j1)+1) = d{j1};
end
2 Kommentare
Walter Roberson
am 13 Dez. 2012
Is the number of matching elements possibly different between the id's? If it is, then you cannot do this with a numeric matrix and need to use a cell array instead.
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