How can I make a for loop with two diferent indexes
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%My problem:
syms w;
for i=1:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%This is fine, but now I want to break the intervals in smaller ones:
syms w;
for i=1:0.2:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%And I want the values of xi(2)/pi() to be saved in a vector, but it want let me. I understand why, but I can't resolve it.
%Thank you very much to you all.
2 Kommentare
Nasser M. Abbasi
am 6 Dez. 2012
Bearbeitet: Nasser M. Abbasi
am 6 Dez. 2012
You are mixing syms with numerics. Decide what you want to do. Either use numerics or symbolic. Very confusing code. Why calling fsolve() with syms?
But in order to make a symbolic vector, do
range=1:0.2:20;
X = sym(zeros(1, length(range)));
Akzeptierte Antwort
Matt Fig
am 6 Dez. 2012
Bearbeitet: Matt Fig
am 6 Dez. 2012
syms w;
cnt = 1:.2:20;
for ii=1:length(cnt)
xi = fsolve(@(w) -tan(w/2) + w/2-4/ii*(w/2).^3,[1 3]*pi-.1);
X(ii) = xi(2)/pi;
end
4 Kommentare
Matt Fig
am 6 Dez. 2012
Nuno, did you run the code? It does exactly what you describe. You want to solve the equation for every value of lam in 1:.2:20 and store the second solution in a vector X. That is what the code does....
Nasser, True enough! I just copied Nuno's code and made the minimal changes.
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