radix 2 disspation in frequency
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
for K=0:7
for N=0:3
if mod(K,2)==0
v(N+1)=(x(N+1)+x(N+5))*exp(-1i*N*K*pi/2);
elseif mod(K,2)==1
v(N+1)=((x(N+1)-x(N+5))*exp(-1i*N*pi/4))*exp(-1i*N*K*pi/2);
end
end
Y(K+1)=sum(v);
end
i assume that is radix 2 disspation in frequency what's wron in it
2 Kommentare
Walter Roberson
am 5 Dez. 2012
Are you seeing an error message? If not then what difference do you see between what you are getting and what you expected?
Antworten (1)
Azzi Abdelmalek
am 6 Dez. 2012
Bearbeitet: Azzi Abdelmalek
am 6 Dez. 2012
x=rand(1,8); % Example
xo=x(2:2:end); % odd part
xe=x(1:2:end); % even part
for N=0:3
for k=0:3
Xo(k+1)=xo(k+1)*exp(-j*2*k*N*pi/4)
Xe(k+1)=xe(k+1)*exp(-j*2*k*N*pi/4)
end
Yo(N+1)=sum(Xo)
Ye(N+1)=sum(Xe)
Y(N+1)=Ye(N+1)+exp(-j*2*N*pi/n)*Yo(N+1)
Y(N+5)=Ye(N+1)-exp(-j*2*N*pi/n)*Yo(N+1)
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Transforms finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!