polynomial evaluation for a simple curve.

2 Ansichten (letzte 30 Tage)
Paul Rogers
Paul Rogers am 30 Jun. 2020
Beantwortet: Paul Rogers am 1 Jul. 2020
After I got the coefficent from the command:
p1=polyfit(x,y,4);
the p1 vector is:
p1 =
-35.4628 39.9257 -14.8278 1.6022 1.1031
the x vector is:
x=[0:0.001:0.4000]
Now, how do I write like this:
I don't need the polyval command.

Akzeptierte Antwort

Paul Rogers
Paul Rogers am 1 Jul. 2020
formula = ((x.^4)*-35.4628) + ((x.^3)*39.9257) + ((x.^2)*-14.8278) + ((x.^1)*1.6022) + ((x.^0)*1.1031);

Weitere Antworten (0)

Kategorien

Mehr zu Polynomials finden Sie in Help Center und File Exchange

Produkte


Version

R2014b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by