Cut part of filename using delimiter

16 Ansichten (letzte 30 Tage)
Nik Rocky
Nik Rocky am 24 Jun. 2020
Kommentiert: Nik Rocky am 24 Jun. 2020
Hello,
i have files:
001_m1_60_const_20200611_200515_SNR_5_PLL.mat
001_m1_60_const_20200611_200515_SNR_10_PLL.mat
001_m1_60_const_20200611_200515_SNR_15_PLL.mat
001_m1_60_const_20200611_200515_SNR_20_PLL.mat
001_m1_60_const_20200611_200515_SNR_25_PLL.mat
001_m1_60_const_20200611_200515_SNR_30_PLL.mat
The problem is, sometimes is a dataname longer or shorter, for exemple:
008_m3_m4_m1_m2_ramp_const_20200111_200415_SNR_25_PLL.mat
I need to cut "_SNR_30_PLL" and get just a:
001_m1_60_const_20200611_200515.mat
my code is not dynamic, and works just with special name length:
name_sep = split(name,"_");
sep = '_';
name_join=[name_sep{1,1} sep name_sep{2,1} ...... .mat];
so i have to join all pieces, witout last three.
How it is works?
Thank you!

Akzeptierte Antwort

Kojiro Saito
Kojiro Saito am 24 Jun. 2020
If you're using R2016b or later, extractBefore might be a good option.
newStr = extractBefore(name, "_SNR");
name_join = strcat(newStr, ".mat");

Weitere Antworten (0)

Kategorien

Mehr zu Characters and Strings finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by