fit data with a line

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Sarah Smith
Sarah Smith am 19 Jun. 2020
Kommentiert: darova am 19 Jun. 2020
ok
  1 Kommentar
darova
darova am 19 Jun. 2020
please don't remove your question

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Ameer Hamza
Ameer Hamza am 19 Jun. 2020
Try something like this
x = linspace(0, 1, 100);
y = 3*x + 2 + rand(size(x));
pf = polyfit(x, y, 1);
y_pred = polyval(pf, x);
r2 = rsquare(y, y_pred); % R-squared
sse = sum((y-y_pred).^2); % SSE
  2 Kommentare
Sarah Smith
Sarah Smith am 19 Jun. 2020
is rsqaure a function?
Ameer Hamza
Ameer Hamza am 19 Jun. 2020

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