" Array dimensions must match for binary array op."

Dear experts,

I need your help;)

I got an Error :" Array dimensions must match for binary array op."

I have 1x14 cell ThAll : { 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double 4-D double}.

Each "4-D double" is a different size matrix . I need to find mean value matrix across all of these 4-D double matrices.

At first , I wanted to make all matrices in one ThAll cell array in the same size with NaN, then add all of them and find one mean value matrix across all matrices. I do it in next way:

for k = 1:length(ThAll)                             % Im not sure if Im making the same size for all matrices right; I think in this part is error
    m = size(ThAll{k},1);
    ThAll{k}(m+1, : , :, :) = NaN;   
end

sum = ThAll{1};                                         % sum of all matrices 
for i = 2:length(ThAll)
    sum = sum + ThAll{i};
end
meanThAll = sum ./ length(ThAll);         % one mean matrix across all matrices in cell array 

Can someone help with this Error :" Array dimensions must match for binary array op" in my case ?

A lot thanks in advance!

[Walter Roberson]

Which MATLAB release are you using? In particular, are you using R2016b or later?

[IM]

Im using R2020a

Answer 1

[Sulaymon Eshkabilov]

Here is one of the easy solutions:

for jj=1:numel(ThAll)
        TH_all=ThAll{jj};
        for kk=1:4
        TH_ALL(jj, kk)=mean2(TH_all(:,:,kk));
        end
end

[IM]

Hey Sulaymon! Thanks so uch for your answer! Anfortunally it dosnt work with my code.

In this way I got new Error : "Brace indexing is not supported for variables of this type". Idont know how to fix it...

[Walter Roberson]

is the error occurring on

TH_all=ThAll{jj};

if so could you confirm that ThAll is still your 1x14 cell array?

[IM]

Hey Walter! Yes, the error "Brace indexing is not supported for variables of this type" occurring on TH_all=ThAll{jj};

After :

for jj=1:numel(ThAll)

TH_all=ThAll{jj};

for kk=1:4

TH_ALL(jj, kk)=mean2(TH_all(:,:,kk));

end

end

ThAll is no more 1x14 cell array . ThAll became simply "4-D double".

[Walter Roberson]

That does not make sense unless it happened before the code you posted.