using for loop with if

1 Ansicht (letzte 30 Tage)
Tyohoon Bay
Tyohoon Bay am 22 Mai 2020
Kommentiert: Tyohoon Bay am 22 Mai 2020
I cannot manage this code, Iam new please help!!!
r1 = 0.103;
x1 = 1.1;
x2 = 1.13;
xm = 59.4;
v_phase = 400 / sqrt(3);
n_sync = 1500;
w_sync =2*pi*50/2;
v_th = v_phase * ( xm / sqrt(r1 (1) ^2 + (x1 + xm )^2) );
z_th = ((j* xm ) * (r1 + j* x1)) / (r1 (1) + j*( x1 + xm ));
r_th = real(z_th);
x_th = imag(z_th);
for m =1:3
if m==1
r2=0.225;
elseif m==2
r2=0.325;
else
r2=0.425;
end
Ik= v_th/(z_th+(j*x2+r2(m)));
fprintf(' Ik = %.f ' \ ', abs (Ik))
end
fprintf(' Ik = %.f ' \ ', abs (Ik))
|
Error: A MATLAB string constant is not terminated properly.

Akzeptierte Antwort

SayedPedram Hosseini
SayedPedram Hosseini am 22 Mai 2020
you havn't defined IK, therefore abs(IK) is unrecognized
besides, in last line you have one( ' ) superfluous. It should be
fprintf(' Ik = %.f \ ', abs (Ik));

Weitere Antworten (1)

James Tursa
James Tursa am 22 Mai 2020
Bearbeitet: James Tursa am 22 Mai 2020
I'm guessing you want a newline at the end?
fprintf(' Ik = %.f \n', abs (Ik))

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by