using for loop with if
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Tyohoon Bay
am 22 Mai 2020
Kommentiert: Tyohoon Bay
am 22 Mai 2020
I cannot manage this code, Iam new please help!!!
r1 = 0.103;
x1 = 1.1;
x2 = 1.13;
xm = 59.4;
v_phase = 400 / sqrt(3);
n_sync = 1500;
w_sync =2*pi*50/2;
v_th = v_phase * ( xm / sqrt(r1 (1) ^2 + (x1 + xm )^2) );
z_th = ((j* xm ) * (r1 + j* x1)) / (r1 (1) + j*( x1 + xm ));
r_th = real(z_th);
x_th = imag(z_th);
for m =1:3
if m==1
r2=0.225;
elseif m==2
r2=0.325;
else
r2=0.425;
end
Ik= v_th/(z_th+(j*x2+r2(m)));
fprintf(' Ik = %.f ' \ ', abs (Ik))
end
fprintf(' Ik = %.f ' \ ', abs (Ik))
|
Error: A MATLAB string constant is not terminated properly.
0 Kommentare
Akzeptierte Antwort
SayedPedram Hosseini
am 22 Mai 2020
you havn't defined IK, therefore abs(IK) is unrecognized
besides, in last line you have one( ' ) superfluous. It should be
fprintf(' Ik = %.f \ ', abs (Ik));
Weitere Antworten (1)
James Tursa
am 22 Mai 2020
Bearbeitet: James Tursa
am 22 Mai 2020
I'm guessing you want a newline at the end?
fprintf(' Ik = %.f \n', abs (Ik))
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!