inverce laplace and ploting data
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
s = zpk('s')
Gs=(9)/(s^2+9*s+9);
pole(Gs)
zero(Gs)
Ct=ilaplace(Gs)
figure
plot(Ct)
2 Kommentare
Antworten (1)
Star Strider
am 16 Mai 2020
I believe that what you actually want is:
s = zpk('s')
Gs=(9)/(s^2+9*s+9);
pole(Gs)
zero(Gs)
% Ct=ilaplace(Gs)
figure
step(Gs)
since under other circumstances (specifically using the Symbolic Math Toolbox), plotting ilaplace of a symbolic transfer function (using fplot) would return the impulse response. To plot a symbolic step response, you would divide ‘Gs’ by ‘s’, then use fplot.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Digital Filter Analysis finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!