How to create a surface for an ODES system that have a variable parameter
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Hi everybody.
I like to make a surface for the following system of odes.

the code of the function is this
function [H, h, ZH, Zh, Z] = fun123(muH)
clear all;
close all;
clc;
%
tic;
rand('state',sum(100*clock)); % seed
%
numreps= 1; % Number of iterations
for j=1:numreps
options = odeset('RelTol',1e-6,'Stats','on');
%Parameters values
aH = 800;
ah = 0.16;
%
bH = 0.73;
bh = 0.73;
%
alphaH = 1.62;
alphah = 1.62;
%
lambdaH = 6.6*10^6;
lambdah = 6.6*10^6;
%
rH = 124*52;
rh = 124*52;
%
muH = 117*52; %this is the parameter that varying
muh = 117*52;
%
muZ = 45*52;
%
betaH = 6*10^-9;
betah = 6*10^-9;
%
phiH = 1*10^4;
phih = 1*10^4;
%
varrhoH1 = 10^-2;
varrhoH = varrhoH1*lambdaH;
%
varrhoh1 = 10^-2;
varrhoh = varrhoh1*lambdah;
%
KH = 1*10^5; % adults host
Kh = 1*10^5; % tadpoles host
KZH = 5.6*10^6; % zoospores tadpoles
KZh = 5.6*10^6; % zoospores tadpoles
%x(1) = H; x(2) = h; x(3) = ZH;
%x(4) = Zh; x(5) = Z;
G = @(t, x, ah, aH, bh, bH, muh, muH, alphah, ...
alphaH, lambdah, lambdaH, rh, rH, phih, phiH, ...
varrhoh, varrhoH, muZ, betaH, betah, Kh, KH, KZH, KZh) ...
[ah * x(2) * exp(-Kh * x(2)) - bH * x(1) - alphaH * x(3); ...
aH * x(1) - (bh + ah * exp(-Kh * x(2))) * x(2) - alphah * x(4); ...
rH * x(3) * exp(-KZH * x(3)) + lambdaH * x(3) * (x(1)./(varrhoH + x(1))) + x(5) * betaH * (x(1)./(x(1) + x(2))) - x(3) * (bH + muH) - alphaH * x(1) * (x(3)./x(1) + (x(3)./x(1))^2 * ((phiH + 1)./phiH)); ...
rh * x(4) * exp(-KZh * x(4)) + lambdah * x(4) * (x(2)./(varrhoh + x(2))) + x(5) * betah * (x(2)./(x(1) + x(2))) - x(4) * (bh + ah * exp(-Kh * x(2)) + muh) - alphah * x(2) * (x(4)./x(2) + (x(4)./x(2))^2 * ((phih + 1)./phih)); ...
lambdaH * x(3) + lambdah * x(4) - x(5) * (muZ + betaH * (x(1)./(x(1) + x(2))) + betah * (x(2)./(x(1) + x(2))))-(lambdaH * x(3) * (x(1)./(varrhoH + x(1))) + lambdah * x(4) * (x(2)./(varrhoh + x(2))))];
tspan = [0:0.00001:80];
x0 = [100 100 10 10 500];
[t,xa] = ode45(@(t,x) G(t, x, ah, aH, bh, bH, muh, muH, ...
alphah, alphaH, lambdah, lambdaH, rh, rH, phih, phiH, ...
varrhoh, varrhoH, muZ, betaH, betah, Kh, KH, KZH, KZh), ...
tspan, x0, options);
H = xa(:,1)';
h = xa(:,2)';
Zh = xa(:,3)';
ZH = xa(:,4)';
Z = xa(:,5)';
end
end
I will like to make a surface that describe the behavior of each solution (H(t), h(t), ZH(t), Zh(t), Z(t)) when a parameter varying, for example \mu_{H}, let say [1000: 500: 6000]. The surface that I want is similar to this figure

Evaluating µH in the range of values given between [1000: 500: 6000]. The code I am implementing to generate the above surface is as follows:
muH = (1*10^3:500:6*10^3);
HMC = [];
ZHMC = [];
fori = 1:length(muH)
[H, ZH] = fun123(muH(i)); %To evaluate each mu values in the function
HMC = [HMC; H];
ZHMC = [ZHMC; ZH];
end
However, I think the result is not correct, since that the \mu_ {H} value does not evaluated correctly within of function.
For example, if I manually evaluate the odes system for a set of values of µ the behavior in H (t) at each value is as follows
If \mu=1000, the graphic of H(t) in 2-D is this

If \mu=2000, the graphic of H(t) in 2-D is this

If \mu=3000, the graphic of H(t) in 2-D is this

In this sense, I hope someone else can I help me for make this surface in 3-D for the range values of \mu
Antworten (1)
Ameer Hamza
am 12 Mai 2020
Inside the function definition, You are again setting it to a constant value
muH = 117*52; %this is the parameter that varying
muh = 117*52;
No matter what you pass as muH input, it gets overwritten and you same constant output. You should remove this line from the function definition.
9 Kommentare
Alvaro Sepulveda
am 12 Mai 2020
Ameer Hamza
am 12 Mai 2020
I think you are directly trying to run your function without passing the value of muH. Are you running this script?
muH = (1*10^3:500:6*10^3);
HMC = [];
ZHMC = [];
fori = 1:length(muH)
[H, ZH] = fun123(muH(i)); %To evaluate each mu values in the function
HMC = [HMC; H];
ZHMC = [ZHMC; ZH];
end
Alvaro Sepulveda
am 12 Mai 2020
Ameer Hamza
am 12 Mai 2020
Oh! I missed it initially. Remove these lines from your function definition
clear all;
close all;
Alvaro Sepulveda
am 13 Mai 2020
Ameer Hamza
am 13 Mai 2020
Does the plot looks correct now?
Alvaro Sepulveda
am 14 Mai 2020
Ameer Hamza
am 14 Mai 2020
You can run
shading interp
to remove the black lines.
Alvaro Sepulveda
am 15 Mai 2020
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