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What am I doing wrong (NEwtons method?)

2 Ansichten (letzte 30 Tage)
Marina Pirzada
Marina Pirzada am 10 Mai 2020
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
Command window says I have an error on line 10. I have no clue whats wrong with my code though.

Antworten (2)

Cris LaPierre
Cris LaPierre am 10 Mai 2020
Much more helpful if you copy/paste the entire error as well as the code.
My initial guess is that you are getting an error that the index must be a positive integer? In your for loop, your loop counter i starts at 1. In you conditional statement on line 10, you use x(i-1). When i=i, it attempts to extract the value at x(0). However, in MATLAB, indexing starts at 1, not 0.
The simplest solution is to have your for loop index start at 2.

Walter Roberson
Walter Roberson am 10 Mai 2020
for i=1:Nmax
so i starts at 1.
if min(abs(x(i)-x(i-1)))<xtol||min(abs(f1(x(i))))<ftol
i is a scalar. x(i) and x(i-1) are scalars. abs() of subtracting two scalars would be a scalar. What is the purpose of taking min() of a scalar?
On the first iteration, i is 1. x(i)-x(i-1) is x(1)-x(1-1) which is x(1)-x(0) . But x(0) is not a legal subscript in MATLAB.
Notice that when you got to that line, you have just computed x(i+1) but you do not use x(i+1) in your test to see if you have finished.

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