Hi my english is not good but i will try.
i need create the next signal:
m2(t)=u(t+1)+6*u(t-3)-10*u(t-6)
u(t):impluse of amplitude equal 1
how i cant do it?
well after i need modulate... but i dont need help in that.
thx :)

3 Kommentare

Azzi Abdelmalek
Azzi Abdelmalek am 28 Okt. 2012
what about the width of your pulse, or are you working with discret time?
Felipe Farias
Felipe Farias am 29 Okt. 2012
well i use a widht very small... but in discrete time would be better.
PD: thx for function
Azzi Abdelmalek
Azzi Abdelmalek am 29 Okt. 2012
if the pulse had a width(even with eps width) that means it's continuous. Check my answer, you can set the width and the amplitude

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Azzi Abdelmalek
Azzi Abdelmalek am 28 Okt. 2012
Bearbeitet: Azzi Abdelmalek am 28 Okt. 2012

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save this function
function p= puls(w,A,t)
% w:pulse width
% A:pulse amplitude
% t:time vector
n=length(t);
p=zeros(1,n);
idx=find(abs(t)<=w/2)
p(idx)=A
then call in your m file call the function
w=4 % the width of your pulse
A=1 % the Amplitude of your pulse
t=-10:0.01:10; % time vector
m2=puls(w,A,t+1)+6*puls(w,A,t-3)-10*puls(w,A,t-6)

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Wayne King
Wayne King am 28 Okt. 2012

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Your signal is just a superposition (sum) of shifted unit step sequences.
For t = -1,0,1,2 m2(t) = 1
For t = 3,4,5 m2(t) = 7
For t = 6,7,8,9,...
m2(t) = -3
u1 = ones(100,1);
u2 = [zeros(4,1); 6*ones(96,1)];
u3 = [zeros(7,1); -10*ones(93,1)];
m2 = u1+u2+u3;
n = -1:98;
stem(n,m2,'markerfacecolor','b')

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