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Sum with a for loop of each 2 elements

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Ali Tawfik
Ali Tawfik am 21 Apr. 2020
Kommentiert: Sriram Tadavarty am 21 Apr. 2020
Hi All,
I have been trying to get the sum of each two elements: for example:
I have x=[50 200 20], I need to have the output =[250 220]
50+200
then
200+20
and so on...
clear all;
clc;
x=[50 200 20];
%x(1:length(x))=x(length(x):-1:1);
for i=1:length(x)-1
c(i) = sum(x); % c(i)=[250 220]
end

Antworten (1)

Sriram Tadavarty
Sriram Tadavarty am 21 Apr. 2020
Bearbeitet: Sriram Tadavarty am 21 Apr. 2020
Hi Ali,
Use the following modification to the code:
clear all;
clc;
x=[50 200 20];
for i=2:length(x)
c(i-1) = x(i-1) + x(i);
end
Use can even use movsum function as shown below:
c = movsum(x,2);
c = c(2:end);
Hope this helps.
Regards,
Sriram
  2 Kommentare
Ali Tawfik
Ali Tawfik am 21 Apr. 2020
Hi Sriram,
Thanks for your prompt reply.
actually I do not prefer functions in that situation,
and even when I tried I got the following error
Subscripted assignment dimension mismatch.
So Would you mind helping me to have a command without function ??
thanks,
Sriram Tadavarty
Sriram Tadavarty am 21 Apr. 2020
Sure Ali. Can you once look over the modified answer?

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