Hi ,i have problem whit the function quad

% -u''=(3/2)*t^(1/2)+(2/3)*t^(3/2)+(2/3)-(2/3)*t, int(u'v')=int(fv)
% u(0)=u(1)=0
clear;figure;
n=10;% Nombre des noeuds
a=0;b=1;
x=linspace(a,b,n);h=(b-a)/(n-1);% Noeuds
syms t ;
f=-(3/2)*t^(1/2)+(2/3)*t^(3/2)+(2/3)-(2/3)*t;
for i=1:n-2
H1=@(t)(x(i+2)-t)/h;
H2=@(t)(t-x(i))/h;
k(i,i)=2/h;
f1=@(t)f.*(x(i+2)-t)/h;
f2=@(t)f.*(t-x(i))/h;
F(i)=quad(f2,x(i),x(i+1))+quad(f1,x(i+1),x(i+2));
end
% Calcul des éléments non diagonaux de la matrice de régidité
for i=2:n-2
k(i-1,i)=-1/h;
k(i,i-1)=k(i-1,i);
end
% Matrice globale de régidité
A=zeros(n-2);
for i=1:n-2
A(i,i)=k(i,i);
end
for i=2:n-2
A(i-1,i)=k(i-1,i);
A(i,i-1)=A(i-1,i);
end
%Vecteur de second memebre du système global
B(:,1)=F(1:n-2);
Uh=zeros(n,1);
Uh(2:n-1)=A\B;% Solution approchée
t=a:.001:b;
u=@(t)2*t.^(3/2)/3-2*t/3 ;% Solution exacte
y=feval(u,t);
plot(t,y),hold on
%m=length(x);
u=@(x)2*x.^(3/2)/3-2*x/3;
U(1:n,1)=feval(u,x(1:n));
Uh(1)=0;Uh(n)=0;
for i=1:n-1
t=x(i):.001:x(i+1);
H2=(t-x(i))/h;
H1=(x(i+1)-t)/h;
uh=Uh(i)*H1+Uh(i+1)*H2;%Expression analytique de la solution approchée
plot(t,uh,'-r')
end
%Affichage des résultats
er=abs(Uh-U);
T(:,1)=x';T(:,2)=U;T(:,3)=Uh;T(:,4)=er;
disp([' x ',' u ',' uh ',' Erreur'])
disp(T)

2 Kommentare

Geoff Hayes
Geoff Hayes am 20 Apr. 2020
Elkalai - please copy and paste the full error message to this question (rather than creating tags of the error message).
Elkalai Mouncif
Elkalai Mouncif am 20 Apr. 2020
Error in quad (line 88)
quadstep(f,x(3),x(5),y(3),y(4),y(5),tol,trace,fcnt,hmin,varargin{:});
Error in methodeVariationnelleGlobale (line 16)
F(i)=quad(f2,x(i),x(i+1))+quad(f1,x(i+1),x(i+2));

Melden Sie sich an, um zu kommentieren.

Antworten (1)

darova
darova am 21 Apr. 2020

0 Stimmen

Make this modifications

Kategorien

Gefragt:

am 20 Apr. 2020

Beantwortet:

am 21 Apr. 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by