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Encounter an error while using fimplicit?

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Wajahat
Wajahat am 16 Apr. 2020
Kommentiert: Star Strider am 16 Apr. 2020
How to plot the following equation on matlab by using fimplicit?
(x-x0).*conj((x-x0))+(y-y0).^2=r^2
close all;
r=1./2;
x0=0;
y0=1./2;
syms x y
fimplicit((x-x0).*conj((x-x0))+(y-y0).^2-r^2)
axis equal
Matlab shows
'Undefined function or variable 'fimplicit'.'

Akzeptierte Antwort

Star Strider
Star Strider am 16 Apr. 2020
The fimplicit function was introduced in R2016b.
Use the contour function instead:
r=1./2;
x0=0;
y0=1./2;
f = @(x,y) (x-x0).*conj((x-x0))+(y-y0).^2-r^2;
xv = linspace(x0-r, x0+r, 25);
yv = linspace(y0-r, y0+r, 25);
[X,Y] = ndgrid(xv,yv);
figure
contour(X,Y,f(X,Y), [0 0])
grid
axis equal
.
  6 Kommentare
Wajahat
Wajahat am 16 Apr. 2020
I got this
which is not same as the previous attached hyperboic image
Star Strider
Star Strider am 16 Apr. 2020
Adjust the limits of ‘xv’ (and perhaps also ‘yv’) to match the figure you want.
For example:
xv = linspace(-1, 1, 25);
You may need to change the parameters in the ‘f’ function to exactly reproduce the figure you posted.

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