Putting random values in for loop
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Hi everyone
I am writing a program in which i am using the following loop.
for t = 1:1:81;
vv(t) = floor(+1*120*sin(2*pi*(t-1)/40));
end
The vales of vv are like 0,18,37...... However, i found that my program has some instability due to jumping directly from vv = 0 to vv = 18. Therefore, my intention is to keep the inputs for the loop as it is (otherwise it gets too long to run), but to put few more input values for vv. for example I want to start with 0, 1, 5, 9, 14, 18,37,....... Hence i need to put those 4 values in between 0 and 18 to bring stability into the result. Can anyone please help me.
Thanks in advance
Hossain
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Akzeptierte Antwort
Jonathan Epperl
am 24 Okt. 2012
Do what Matt suggested:
VV = floor(+1*120*sin(2*pi*(t-1)/40));
Then add your extra values into VV:
VV = [VV(1) 1 5 9 14 VV(2:end)];
Then run your loop
for i=1:numel(vv) % presumably 85
vv = VV(i);
% your other code
end
Weitere Antworten (1)
Matt Kindig
am 24 Okt. 2012
Hi Sazzad,
First of all, you don't need the loop: you can just do it like this:
vv = floor(+1*120*sin(2*pi*(t-1)/40));
Second, can you just use a finer resolution of t, such as:
t= 1:0.1:81;
vv = floor(+1*120*sin(2*pi*(t-1)/40));
Now vv changes from 0 to 1 to 3 to 5, etc.
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