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gaussian beam height plot

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Win Thomas Halim
Win Thomas Halim am 10 Apr. 2011
hi there, is there any matlab code that return the value of a 3d plot? for example: mu = [1 2;-3 -5]; sigma = cat(3,[2 0;0 .5],[1 0;0 1]); p = ones(1,2)/2; obj = gmdistribution(mu,sigma,p);
ezsurf(@(x,y)pdf(obj,[x y]),[-10 10],[-10 10])
so i got this graph so simulate my gaussian beam for nanomachining, the problem is by using this m file, i cant specify the height of the beam. i think the only one way is to return the z value of the graph, and multiply by certain coefficient that reach the height that i want then regraph it. any help would be much appreciated.
thank you
  1 Kommentar
Oleg Komarov
Oleg Komarov am 10 Apr. 2011
Can you format the code?

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Oleg Komarov
Oleg Komarov am 10 Apr. 2011
Can you be more specific? What do you want to do with the graph?
Also, pdf map the domain into the [0 1] interval. You can't have more than 100% probability.
If you are just trying to set values for the z axis then:
set(gca,'zlim',[0,1])
or
inspect(gca)
  2 Kommentare
Win Thomas Halim
Win Thomas Halim am 10 Apr. 2011
yes, i know i cant get more than 100% probability, thats why i need the values of z from my graph. from there i will be able to edit it at certain height.
here my task is to plot a 3d graph projecting a focused ion beam milling a material. the milling should be looks like gaussian distribution for each point. therefore i find the gmdistribution command come in handy to project the milling, but the problem is i cant modify the height. the result should be like:
http://img8.imageshack.us/i/fibn.jpg
i dont know how to format the code, therefore i just copy and paste it here:
mu = [1 2;-3 -5];
sigma = cat(3,[2 0;0 .5],[1 0;0 1])
p = ones(1,2)/2;
obj = gmdistribution(mu,sigma,p);
ezsurf(@(x,y)pdf(obj,[x y]),[-10 10],[-10 10])
just need to know how to set the height.
thank you very much oleg.
Oleg Komarov
Oleg Komarov am 10 Apr. 2011
To get the values of z call:
h = ezsurf(@(x,y)pdf(obj,[x y]),[-10 10],[-10 10])
get(h, 'zdata')

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Win Thomas Halim
Win Thomas Halim am 11 Apr. 2011
thank you Mr. Komarov, thats very helpfull!

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