I would like to create a matrix using a for loop
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Rodrigo Blas
am 13 Apr. 2020
Kommentiert: Rodrigo Blas
am 13 Apr. 2020
function rn=Ljallo_f_q1(T,R,pnh3,po2)
for i=1:3
A=zeros(3,1);
B=zeros(3,1);
C=zeros(3,1);
rn=zeros(3,1);
rn(i)=A(i)/(B(i)*C(i));
A(i)=3.4*10^-8*exp(21700/(R.*T(i)))*pnh3*po2^(.5);
B(i)=1+8*10^-2*exp(4400/(R.*T(i)))*po2^(.5);
C(i)=1+1.6*10^-3*exp(25500/(R.*T(i)))*pnh3;
end
pnh3=.046; %%torr
po2=.068; %%torr
R=62.364*1000; %%cm^3*torr/K*g-mol
T=zeros(3,1);
T(1)=473;
T(2)=673;
T(3)=800;
z=Ljallo_f_q1(T,R,pnh3,po2);
>> Ljallo_s_q1
>> z
z =
0
0
NaN
I would like to create amatrix rn with 3 values(rn(1) rn(2) rn(3)) using a for loop
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Akzeptierte Antwort
Rik
am 13 Apr. 2020
If you had used the debugging tools, you would have noticed that your variables are reset every iteration.
You need to move assignments like A=zeros(3,1) outside of the loop.
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