generating sequence number with time sampling
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Nur Amalina
am 8 Apr. 2020
Kommentiert: Nur Amalina
am 8 Apr. 2020
Hi all!
I need to update the value of a. for t=1:1000.
while there is time sampling tk which has the sequence like this [0 2 5 7 10 12 15 .... 55 57 60]
i was trying the code below. but it doesn't work. may anyone help me? thanks in advance!
for t = 1:1000
if mod(t,2)==1
p=2;
else
p=3;
end
tk(1)=0;
tk(t+1)=tk(t)+p;
if t==tk
a(x)=a(x)+1
else
a(x)=a(x)
end
end
0 Kommentare
Akzeptierte Antwort
Andrei Bobrov
am 8 Apr. 2020
Bearbeitet: Andrei Bobrov
am 8 Apr. 2020
out = cumsum([0;rem(0:23,2)' + 2]);
for "t = 1:1000":
t = (1:1000);
tt = mod(t,2);
out = cumsum([0;2 + tt(2:end)]);
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!