plot values in the loop

Hello

my code is something like this

p=3
for k=1:p
    %something
    if %something
        d=d+1
    elseif %something
        d=d-2
    end
    plot(k,d,'o')
    hold on
end

I get three values of d corresponding to three values of k. I want to plot these values so that the x axies will be the values of k and the y axis will be the values of d

The thing is, with this code I get only points, but I want to link them with lines. How can I do that?

Thank you

[KSSV]

whats is that something?

[Mehmed Saad]

the easiest way is to store your variables in a vector with each iteration and plot them at the end of for loop, in this way they will be joined together

[Ani Asoyan]

I've tried with vectors, but the thing is,,, d is a variable that is defined in a separate function file,, and when I make it a vector, it gives me errors

Answer 1

[Jakob B. Nielsen]

do

plot(k,d,'o-')

instead, that will give you o's connected by lines.

[Mehmed Saad]

i don't think so sir

it wont

try it

[Ani Asoyan]

sorry it didn't work

Answer 2

[KSSV]

p=3 ;
k = 1:p ; 
val = zeros(1,p) ; 
for i = 1:length(p)
    %something
    if %something
        d=d+1
        val(i) = d ; 
    elseif %something
        d=d-2
        val(i) = d ; 
    end
end
plot(k,val,'-o')

[Mehmed Saad]

p=3 ;
k = 1:p ; 
val = zeros(1,p); 
for i = 1:p             % here either p or length(k)
    %something
    if %something
        d=d+1
        val(i) = d ; 
    elseif %something
        d=d-2
        val(i) = d ; 
    end
end
plot(k,val,'-o')

[Ani Asoyan]

It says "Vectors must be the same length." in either way.

when I type k in command window it shows

k =
     1     2     3

but val is

val =
         0         0         0   -0.1000

moreover, val only stores d's last value which is -0.1 ...like it adds this value to the vector of zeros

[KSSV]

Show us the full code which gave this result.

[Ani Asoyan]

clear all
close all
clc

%defining government's steps
x1=0;
x2=1;

%defining public's steps
x_e1=0;
x_e2=1;

%defining reforms
N1=0;
N2=1;

%combinations
A=[x1, x2 ];
B=[N1, N2];
C=[x_e1, x_e2];
[m,n,p] = ndgrid(A,B,C);
Z = [m(:),n(:),p(:)];

p=3

d=0.5
k=1:p;
val=zeros(1,p);

for i=1:length(p)
    
%parameterizing function of government's payoff
a=2; b=2; c=0.5; e=0.5;
u_g = @(x, x_e, N)(-0.5*a*x.^2+b*(x-x_e)-c*N+e*u_p(x,x_e,N, d));

%linking government's payoff function to data
g=(u_g(Z(:,1),Z(:,3), Z(:,2) ).');

%linking public's payoff function to data 
p=(u_p(Z(:,1), Z(:,3), Z(:,2),d).'); 

gp=reshape(g,[4,2]).' ;%government's payoff matrix

pp=reshape(p, [4,2]).' ;%public's payoff matrix

num2strcell = @(m) arrayfun(@num2str, m, 'UniformOutput', false);  %function to convert matrix to cell array of strings
payoffs=strcat(num2strcell(gp), num2strcell(pp))

n=4; m=2;

for i=1:n
A(i)=max(pp(:,i));
attainedA=(max(pp, [] ,1)==pp);
end

for v=1:m
 if all(A==pp(v,:))
        fprintf('a dominant strategy for public is %d\n',v');
    else fprintf ('No dominant strategy for public');
 end
end

for j=1:m
 B(j)=max(gp(j,:));
 attainedB=( max(gp,[],2)==gp );
end

for l=1:n
  if all (B==gp(:,l))
      fprintf('a dominant strategy for government is %d\n',l');
   else fprintf ('No dominant strategy for government');
   end
end

result = payoffs(attainedA & attainedB)

gov=gp(attainedA & attainedB)

pub=pp(attainedA & attainedB)

T = array2table(payoffs,'VariableNames',{'X1_N1','X2_N1','X1_N2','X2_N2'},'RowNames',{'x_e1','x_e2'})

  if (gov==gp(1,1) || gov==gp(2,1) || gov==gp(1,2) || gov==gp(2,2) )
    d=d-0.2
    val(i)=d;
  elseif (gov==gp(1,3) || gov==gp(2,3) || gov==gp(1,4) || gov==gp(2,4) )
        d=d+3
        val(i)=d
    
  end
d
end 
plot(k,val,'-o')

and there is also one function

function u=u_p(x,x_e,N,d)

u = -(x-x_e).^2+N.*d;
end