Pulling data from a for loop
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Justin Hayes
am 27 Mär. 2020
Kommentiert: Justin Hayes
am 28 Mär. 2020
I want to subtract Tskin at t = 10 from Tskin at t = 9. How do I do this?
T = 29; % %C
Tambient = 20; % C
Tfilm = (T + Tambient)/2;
for t = 1:1:100
k_air_2 = (2.4131 + 0.0078 * T) * 10^-2; % W/m*C
rho_air = 1.2893 - 0.004 * Tfilm; % kg/m^3
mu_air = (0.0047 * Tfilm + 1.7164) * 10^-5; % kg/m*s
k_air_ambient= (2.4131 + 0.0078 * Tfilm) * 10^-2; % W/m*C
Re = Diameter_forearm * V * rho_air / mu_air;
h_air = (k_air_ambient/Diameter_forearm) .* (0.3 + ((0.62 * Re.^.5 * Pr.^.333)/((1 + (0.4 * Pr).^.667).^.25)).*(1 + ((Re/282000).^(5/8))).^.8) % J/s*K*m^2
Uskin = (k_air_2/thickness_air) + (k_cotton/thickness_shirt) + (h_air) % J/s*K*m^2
Uambient = (k_air_ambient/thickness_air) + (k_cotton/thickness_shirt) + (h_air)
Tskin = [(T * Area * Cp_air * rho_air)/(t-(t-1)) + Qgen + (Uambient * Area * Tambient)]/((Area * Cp_air * rho_air / ((t-(t-1)))) + Uskin * Area);
T = Tskin
Tfilm = (T + Tambient)/2
fprintf('Y is %.2f C after %d seconds ' ,Tskin,t)
end
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Walter Roberson
am 27 Mär. 2020
T = 29; % %C
Tambient = 20; % C
Tfilm = (T + Tambient)/2;
Tskin = nan;
for t = 1:1:100
k_air_2 = (2.4131 + 0.0078 * T) * 10^-2; % W/m*C
rho_air = 1.2893 - 0.004 * Tfilm; % kg/m^3
mu_air = (0.0047 * Tfilm + 1.7164) * 10^-5; % kg/m*s
k_air_ambient= (2.4131 + 0.0078 * Tfilm) * 10^-2; % W/m*C
Re = Diameter_forearm * V * rho_air / mu_air;
h_air = (k_air_ambient/Diameter_forearm) .* (0.3 + ((0.62 * Re.^.5 * Pr.^.333)/((1 + (0.4 * Pr).^.667).^.25)).*(1 + ((Re/282000).^(5/8))).^.8) % J/s*K*m^2
Uskin = (k_air_2/thickness_air) + (k_cotton/thickness_shirt) + (h_air) % J/s*K*m^2
Uambient = (k_air_ambient/thickness_air) + (k_cotton/thickness_shirt) + (h_air)
old_Tskin = Tskin;
Tskin = [(T * Area * Cp_air * rho_air)/(t-(t-1)) + Qgen + (Uambient * Area * Tambient)]/((Area * Cp_air * rho_air / ((t-(t-1)))) + Uskin * Area);
T = Tskin
Tfilm = (T + Tambient)/2
fprintf('Y is %.2f C after %d seconds ' ,Tskin,t)
if t==10
fprintf('Tskin(10) - Tskin(9) = %g\n', Tskin - old_Tskin);
end
end
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