Info

Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.

Various errors whilst running a while loop.

4 Ansichten (letzte 30 Tage)
Sam Potter
Sam Potter am 14 Mär. 2020
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
h(1)=100000; %initial Height
t(1)=0; %Initial Time
dt=0.005;
p(1)=(((h(1))/71)+1.4); %Air Density
g(1)=(40*10^7)/(6371+h(1))^2; %initial gravity
A=5; %Area
c=0.7; %Drag Coefficient
m=850; %Mass
Fd(1)=0.5*c*(p(1))*a(1)*(v(1))^2;
v(1)=59.29; %Initial velocity
a(1)=0.03535; %Initial Acceleration
i=1; %Loop Counter
while h(end)>=0
t(i+1)=t(i)+dt;
h(i+1)=100000-((v(i+1)*t(i+1))+(0.5*(a(i))*(t(i+1))^2));
p(i+1)=(((h(i+1))/71)+1.4);
Fd(i+1)=0.5*c*(p(i+1))*A*(v(i+1))^2;
g(i+1)=(40*10^7)/(6371+h(i+1))^2;
a(i+1)=g(i+1)-(Fd(i+1)/850);
v(i+1)=v(1)+(a(i+1)*t(i+1));
end
With this code I want to be able to plot graphs and get values for a and v. When I run it an error comes up either saying 'undefined function or variable a'. or 'undefined function or variable v'. One time I managed to stop these errors but I still got an error saying 'Index exceed number of array elements'. Any help would be appreciated.
  6 Kommentare
Walter Roberson
Walter Roberson am 14 Mär. 2020
h(i+1)=100000-((v(i+1)*t(i+1))+(0.5*(a(i))*(t(i+1))^2));
When i is 1, that tries to use v(1+1) and t(1+1) and a(1) . You assigned to t(1+1) in the previous line of code, so that exists, and a(1) exists . But v(2) does not exist yet, and will not exist until the end of the loop (and it relies upon the updated a(2) so you cannot just move it to earlier in the code.)
Sam Potter
Sam Potter am 14 Mär. 2020
This is my current code now:
>> clear
>> h(1)=100000; %initial Height
t(1)=0; %Initial Time
dt=0.005;
p(1)=(((h(1))/71)+1.4); %Air Density
g(1)=(40*10^7)/(6371+h(1))^2; %initial gravity
A=5; %Area
c=0.7; %Drag Coefficient
m=850; %Mass
Fd(1)=0.5*c*(p(1))*a(1)*(v(1))^2;
v(1)=59.29; %Initial velocity
a(1)=0.03535; %Initial Acceleration
i=1; %Loop Counter
while h(end)>=0
t(i+1)=t(i)+dt;
h(i+1)=100000-((59.29*t(i+1))+(0.5*(a(i))*(t(i+1))^2));
p(i+1)=(((h(i+1))/71)+1.4);
Fd(i+1)=0.5*c*(p(i+1))*A*(v(i))^2;
g(i+1)=(40*10^7)/(6371+h(i+1))^2;
a(i+1)=g(i+1)-(Fd(i+1)/850);
v(i+1)=v(1)+(a(i+1)*t(i+1));
end
I have tried to make it so that everything in the loop is defined previously. However, for some reason my code doesnt save some of the initial variables (like u(1) and v(1) into the workspace?

Antworten (1)

Sriram Tadavarty
Sriram Tadavarty am 14 Mär. 2020
  1 Kommentar
Sam Potter
Sam Potter am 14 Mär. 2020
Hi, because the code was different I thought it warrented a diiferent thread, apologies if not. I have replied to you in the other thread with my issue.

Diese Frage ist geschlossen.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by