hi,Can i divide the matrix into layers ,outer layer(boundary elements)then second layer and so on.
for example
original matrix is
1 2 3 4 5 6 7 8
9 10 11 12 13 14 15 16
17 18 19 20 21 22 23 24
25 26 27 28 29 30 31 32
33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48
49 50 51 52 53 54 55 56
57 58 59 60 61 62 63 64
After one bit right shift of outside boundary and inside layers (its like contour)
9 1 2 3 4 5 6 7
17 18 10 11 12 13 14 8
25 26 27 19 20 21 15 16
33 34 35 36 28 22 23 24
41 42 43 37 29 30 31 32
49 50 44 45 46 38 39 40
57 51 52 53 54 55 47 48
58 59 60 61 62 63 64 56

 Akzeptierte Antwort

David Hill
David Hill am 29 Feb. 2020

0 Stimmen

Not sure if there is an easier way, but this does it for you.
function M=matShift(M)
x=size(M,1);
for k=1:floor(x/2)
z=x-2*(k-1)-1;
y=circshift([M(k,k:end-k),M(k:end-k,end-k+1)',M(end-k+1,end-k+1:-1:k+1),M(end-k+1:-1:k+1,k)'],1);
M(k,k:end-k)=y(1:z);
M(k:end-k,end-k+1)=y(z+1:2*z);
M(end-k+1,end-k+1:-1:k+1)=y(2*z+1:3*z);
M(end-k+1:-1:k+1,k)=y(3*z+1:4*z);
end

4 Kommentare

sadiqa ilyas
sadiqa ilyas am 29 Feb. 2020
It works .Thank you so much
sadiqa ilyas
sadiqa ilyas am 29 Feb. 2020
so how to get the original matrix back
David Hill
David Hill am 29 Feb. 2020
Just assign to a different variable at beginning
m=M;
sadiqa ilyas
sadiqa ilyas am 1 Mär. 2020
thanks

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