# Matrix dimensions must agree error in FOR loop

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Ali Tawfik am 29 Jan. 2020
Bearbeitet: James Tursa am 29 Jan. 2020
Hi all,
I am trying to do a conditional statement inside for loop, I got a very strange error of matrix dimensions must agree because I am not working with arrays at all,
the code is the following ( I am using MATLAB 2016a):: ANY HELP PLEASEEEE
for seg_nu=1:input('enter segment numbers: ')
z=input('Is segment parallel to the y axis y/n','s')
if z=='n';
z=1
elseif z=='y';
z=2
else
z=3
end
end
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Ali Tawfik am 29 Jan. 2020
clear all
close all
clc
for seg_nu=1:input('enter segment numbers: ')
z=input('Is segment parallel to the y axis y/n','s')
if z=='no';
z=1
elseif z=='yes';
z=2
else
z=3
end
end
Ali Tawfik am 29 Jan. 2020
line 7
Error using ==
Matrix dimensions must agree.
Error in segment_trial (line 7)
if z=='no';

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### Antworten (1)

James Tursa am 29 Jan. 2020
Bearbeitet: James Tursa am 29 Jan. 2020
This comparison:
z == 'no'
compares z to a 1x2 array.
And this comparison
z == 'yes'
compares z to a 1x3 array.
So you are in fact dealing with arrays here. Suppose you had entered 'yes' as the input, then guess what happens:
>> 'yes' == 'no'
Error using ==
Matrix dimensions must agree.
You get an error because you are comparing a 1x3 array to a 1x2 array. To make string comparisons, use string compare functions designed for it. E.g., strcmpi
if strcmpi(z,'no') || strcmpi(z,'n')
etc.
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