How to make a loop to do a specific operation for multiple variables?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
lambda = num(:,1);
RefInd1 = num(:,2);
RefInd2 = num(:,3);
RefInd3 = num(:,4);
% For the draw ratio DR=1.00
ny1 = interp1(lambda,RefInd1, 590);
nb1 = interp1(lambda,RefInd1, 485);
nr1= interp1(lambda,RefInd1, lambda(end));
abbenumber1 = ((ny1-1)/(nb1-nr1))
% For the draw ratio DR=1.05
ny2 = interp1(lambda,RefInd2, 590);
nb2 = interp1(lambda,RefInd2, 485);
nr2 = interp1(lambda,RefInd2, lambda(end));
abbenumber2 = ((ny2-1)/(nb2-nr2))
% For the draw ratio DR=1.10
ny3 = interp1(lambda,RefInd3, 590);
nb3 = interp1(lambda,RefInd3, 485);
nr3= interp1(lambda,RefInd3, lambda(end));
abbenumber3 = ((ny3-1)/(nb3-nr3))
I want to make a loop to apply this equation (abbenumber) for the different variables of (RefInd1, RefInd2 ...).
0 Kommentare
Antworten (1)
KALYAN ACHARJYA
am 12 Jan. 2020
Bearbeitet: KALYAN ACHARJYA
am 12 Jan. 2020
Assuming those results are array, hence used cell array { }. If numeric, please change to array [ ]
RefInd={};
ny=cell(1,3);;nb=cell(1,3);;nr=cell(1,3); abbenumber=zeros(1,3);
lambda = num(:,1);
for k=2:4
RefInd{k} = num(:,k);
end
for i=1:3
% For the draw ratio DR=1.00
ny{i}= interp1(lambda,RefInd{i}, 590);
nb{i}= interp1(lambda,RefInd{i}, 485);
nr{i}= interp1(lambda,RefInd{i}, lambda(end));
abbenumber(i) = ((ny{i}-1)/(nb{i}-nr{i}))
end
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!