To arrange matrix based off criteria in column

1 Ansicht (letzte 30 Tage)
Cside
Cside am 4 Dez. 2019
Kommentiert: Star Strider am 4 Dez. 2019
Hi i have a 60x2 matrix, with the first column being a number from 1 to 300 (not consecutive), and the second column with locations from 1 to 9. I have attached a picture to show how it looks like and would like to regroup into a new matrix (AB) of 9x____, the rows being the locations (1:9), and the columns being the numbers that have the respective locations i.e. in the first column, if numbers 8, 16 & 52 have a corresponding location 1 in column 2, AB row 1 will be 8,16,52 (1 in each column, total 3 columns). What functions should I use for this/any ideas how to write for this?
Thank you! :)
ferfw.JPG

Akzeptierte Antwort

Star Strider
Star Strider am 4 Dez. 2019
Try this:
Col1 = randperm(300); % Create Column 1
Col2 = randi(9, 1, 300); % Create Column 2
M = [Col1(:) Col2(:)]; % Create Matrix
Gather = accumarray(M(:,2), M(:,1), [], @(x){x.'}); % Cell Array With Desired Information
AB = {(1:9).', Gather};
That should work. You will need to keep ‘AB’ as a cell array because there are different numbers of columns in each row. You might be able to use a structure to store this information, however I doubt that a table would work correctly.
Experiment to get the result you want.
  2 Kommentare
Cside
Cside am 4 Dez. 2019
Thanks star strider! Played around with it and got it :)
Star Strider
Star Strider am 4 Dez. 2019
As always, my pleasure!
To get the individual rows of ‘AB’:
Row1 = [AB{1}(1) AB{2}{1}]
Row2 = [AB{1}(2) AB{2}{2}]
and so for the rest.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by