while-loop condition - arrays equal within a tolerance

Hi guys!

I simplified the problem according to my issue. I basicly want to iterate arrays within a while function. But as soon as one element of the array is true, the while loop is not executed anymore. I want that the while looping is iterating until all elements of the arrays are euqal within a tolerance.

A = [5,2,1,0,0];
B = [4,1,0,0,0];


for i = 1:5
 i = i+1
    while not(A-B < 0.1*ones(5,1)) & ...

        disp('Increase B')
     B = B + 0.01;


    end
end

Answer 1

[Nicolas B.]

for you case, I understand that you want the maximum absolute difference being below a limit?

In that case, the "stay in" condition is:

while max(abs(A-B), [], 'all') > you_limit
   ... 
end
    

the option on the max function is to ensure that you return 1 maximum whatever size have A and B.

[Marko]

This is it! Thank you!