Complement of an Image using loop

Antworten (1)

darova
darova am 8 Nov. 2019

0 Stimmen

Use this trick
for i = 1:m % rows
for j = 1: round(n/m*(m-i+1)) % columns
I(i,j) = original;
end
for j = round(n/m*(m-i+1)):n % columns
I(i,j) = modificated;
end
end

2 Kommentare

Sadeq Ebrahimi
Sadeq Ebrahimi am 8 Nov. 2019
Thanks for for the answer!
I used your trick:
I=imread('4.jpg');
[m,n]=size(I)
for i = 1:m % rows
for j = 1: round(n/m*(m-i+1)) % columns
I(i,j) = original;
%I = I(i,j);
end
for j = round(n/m*(m-i+1)):n % columns
I(i,j) = modificated;
% imcomplement(I) = I(i,j);
end
end
figure(1),imshow(I);
but the output is like this:
Screenshot (13).png
darova
darova am 8 Nov. 2019
Can'b believe. HOw is this possible?

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