How to find an equation of the tangent line to the curve f(x,y) =0 at the....
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
the points (2.4, -2.7927) and (2.4, 2.7127)
f(x,y) = 4x + 2y -xy +3x^2 -5y^2 +5
3 Kommentare
Antworten (1)
Mani Teja
am 31 Okt. 2019
Hello Peter,
This should help:
syms x y f(x,y)
f(x,y) = 4*x + 2*y -x*y +3*x^2 -5*y^2 +5;
a = f(2.4, -2.7927);
a = vpa(a,4); % Just to make it look better
b = f(2.4, 2.7127) ;
b = vpa(b,4);
Regards
Mani
0 Kommentare
Siehe auch
Kategorien
Mehr zu Calculus finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!