# Indexing sections of arrays

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Mohammed Kagalwala am 23 Okt. 2019
Is there an easy way to extract every section's of n elements of a vector in MATLAB and skip the next n? Say we have
x = linspace(1,10,10); %[1 2 3 4 5 6 7 8 9 10]
I wish to index such that I grab 1,2,3 then skip 4,5,6 and again grab 7,8,9. For example,
a = zeros(1,10); % [0 0 0 0 0 0 0 0 0 0]
a(magic index) = x(magic index)
So now a = [1 2 3 0 0 0 7 8 9 0]
I've only been able to find how to get every nth element but not chunks of n elements.
##### 2 KommentareKeine anzeigenKeine ausblenden
Jan w am 23 Okt. 2019
Define the indices you wish to extract
a = [1,2,3,7,8,9];
x = x(a);
Is this what you mean?
Mohammed Kagalwala am 23 Okt. 2019
Not exactly. I don't want a vector [1,2,3,7,8,9]. I want my 'a' vector to be [1 2 3 0 0 0 7 8 9 0]. Jos's answer below works as I wish !

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### Akzeptierte Antwort

Jos (10584) am 23 Okt. 2019
Bearbeitet: Jos (10584) am 23 Okt. 2019
x = 101:110
n = 3
tf = mod(0:numel(x)-1, 2*n) < n
a = zeros(size(x))
a(tf) = x(tf)
index = find(tf)
##### 1 Kommentar-1 ältere Kommentare anzeigen-1 ältere Kommentare ausblenden
Mohammed Kagalwala am 23 Okt. 2019
Thank you ! Works perfectly :)

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