how to replace the element with random number based if statement

Helllo everyone
i have a problem to change element of array with iteration approach. refer to https://www.mathworks.com/matlabcentral/answers/8817-how-to-replace-the-elements-of-a-matrix-using-the-conditions-if-else , i have same problem but little different. for instance i have mut1 = [.11 .12 .13 .14 .15 .16 .17 .18 .19 .20] and constan number 0.5. i want to replace element of mut1 with 'random number between' if random number(rmi) < 0.5. so this is what iam doing.
mutC = zeros(size(mut1));
pm = 0.5;
for i = 1:numel(mut1)
rmi = rand(1,1)
rCm = rbC+(raC-rbC).*rand(1,1)
if rmi<pm
mutC = rCm
else
mutC = mut1
end
end
but the final result is always mutC = mut1. there is no number from rCm.
I will appreciate any help. thank you.

 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 16 Okt. 2019
Bearbeitet: Andrei Bobrov am 16 Okt. 2019
mutC = mut1;
[m,n] = size(mut1);
pm = 0.5;
rmi = rand(m,n);
rCm = rbC+(raC-rbC).*rand(m,n);
for i = 1:numel(mut1)
if rmi(i) < pm
mutC(i) = rCm(i);
end
end
or
pm = .5;
mutC = mut1;
[m,n] = size(mut1);
rCm = rbC+(raC-rbC).*rand(m,n);
lo = rand(m,n) < pm;
mutC(lo) = rCm(lo);

3 Kommentare

thank you for you fast reply sir. one more question sir. how i can store the random value "rCm'? because i have to submit 'rCm' value.
thank you.
many thanks sir. 2 thumbs up..
GBU.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

sid Chen
sid Chen am 16 Okt. 2019
Andrei Answer is very clear.
The problem is
if rmi<pm
mutC = rCm
else
mutC = mut1
with these code, you replace the whole matrix, all the elements are replaced.
To avoid this, you need to replace only one elements step by step. Just add an subscipt 'i' to point the element to be repalced.
if rmi<pm
mutC(i) = rCm(i)
else
mutC(i) = mut1(i)

2 Kommentare

when i run this code become error "index exceeds matrix dimensions"
if rmi<pm
mutC(i) = rCm % change here, rCm is a number,not a matrix
else
mutC(i) = mut1(i)

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Produkte

Version

R2016b

Gefragt:

am 16 Okt. 2019

Kommentiert:

am 17 Okt. 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by