Storing column vectors over a while loop

11 Ansichten (letzte 30 Tage)
Juan Pablo  Arango
Juan Pablo Arango am 8 Okt. 2019
Beantwortet: David Hill am 8 Okt. 2019
Hi I'm having problems with my code. When it goes to the second while loop it does not record the values(.i.e it stops giving me the error that array position values most be logical or positive integers). Any hints on how to solve this?
N = 100
B = [-30 -10 0 0; -10 -30 -10 0; 0 -10 -30 -10; 0 0 -10 -30];
h = 50/2N ;
n = 1;
x = zeros(4,10/h);
x(:,1) = [1;0;0;1];
euclidean_norm(n) = 0;
time(n) = 0;
time_end = 10;
while n<=3
time(n+1) = time(n)+h;
x(:,n+1) = x(:,n) + h*B*x(:,n);
euclidean_norm(n+1) = norm(x(:,n));
n=n+1;
end
while time(n)+h < time_end + eps(1)
time(n+1) = time(n)+h;
x(:,n+1) = x(:,n) + h((23/12)*B*x(:,n)-(16/12)*B*x(:,n-1)+(5/12)*B*x(:,n-2));
euclidean_norm(n+1) = euclidean_norm(x(:,n+1));
n = n + 1;
end
plot(time(1:n),euclidean_norm(1:n))

Antworten (1)

David Hill
David Hill am 8 Okt. 2019
N = 100;
B = [-30 -10 0 0; -10 -30 -10 0; 0 -10 -30 -10; 0 0 -10 -30];
h = 50/(2*N);%I believe this is what you wanted.
n = 1;
x = zeros(4,10/h);
x(:,1) = [1;0;0;1];
euclidean_norm(n) = 0;
time(n) = 0;
time_end = 10;
while n<=3
time(n+1) = time(n)+h;
x(:,n+1) = x(:,n) + h*B*x(:,n);
euclidean_norm(n+1) = norm(x(:,n));
n=n+1;
end
while time(n)+h < time_end + eps(1)
time(n+1) = time(n)+h;
x(:,n+1) = x(:,n) + h*((23/12)*B*x(:,n)-(16/12)*B*x(:,n-1)+(5/12)*B*x(:,n-2));%Need h*
euclidean_norm(n+1) = norm(x(:,n+1));%I believe you want norm(x(:,n+1)) instead of euclidean_norm which causes error.
n = n + 1;
end
plot(time(1:n),euclidean_norm(1:n))

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by