# using a function to answer new questions

1 Ansicht (letzte 30 Tage)
jacob Mitch am 1 Okt. 2019
Kommentiert: jacob Mitch am 1 Okt. 2019
I have created
function y=Gss(n);
a=3; b=0.2; N(1)=0.2;
for v=2:n+1
N(v)=exp(-a*N(v-1)^2)+b;
end
y=N(v);
How would I use this code to calculate something like
if abs(N(v-1)-N(v))<5
else v=v+1 'till you get the desired v'
end
Do I create another script and call Gss(n) or how would I write it in the first function file. I think I would have to use a loop for the second code
##### 0 Kommentare-2 ältere Kommentare anzeigen-2 ältere Kommentare ausblenden

Melden Sie sich an, um zu kommentieren.

### Akzeptierte Antwort

David Hill am 1 Okt. 2019
function [N,answer] = Gss(n);
N=zeros(1,n+1);
a=3; b=0.2; N(1)=0.2;
for v=2:n+1
N(v)=exp(-a*N(v-1)^2)+b;
if abs(N(v-1)-N(v))<5
end
end
end
Or you could just wait to get array N back and then:
function N = Gss(n);
N=zeros(1,n+1);
a=3; b=0.2; N(1)=0.2;
for v=2:n+1
N(v)=exp(-a*N(v-1)^2)+b;
end
end
%once array N comes back
answer=find(abs(diff(N))<5)+1;%this provides multiple answers if multiple differences are <5
##### 1 Kommentar-1 ältere Kommentare anzeigen-1 ältere Kommentare ausblenden
jacob Mitch am 1 Okt. 2019
Hi Thanks David this really allows me to understand well, I just wanted to ask am I able to retain the first y=N(v) that I get from inputing n into Gss(n) value say answer1 and then proceed to calculate the second part as the smallest v such that abs(N(v) -N(v-1))<5 say answer2 whilst outputing each value of N(v) in the iteration.

Melden Sie sich an, um zu kommentieren.

### Kategorien

Mehr zu Line Plots finden Sie in Help Center und File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by