Help Plotting Piecewise functions

I need help plotting the following piecewise function. I attatched the question.

This is what I have so far:

syms x
y = piecewise(0<=x<=3, 4*x^1/3, 3<x<=6, pi^x+e) % this is the line that is saying there is an error. 
fplot(y)

Answer 1

[Walter Roberson]

Chaining equalities like that is only supported in very recent MATLAB. Also you are using the wrong exponent:

y = piecewise(0<=x & x<=3, 4*x^1/3, 3<x & x<=6, pi^(x+e))

If e is intended to be the base of the natural logs then chances are you are going to need to define e as e is not built-in constant in MATLAB. e = exp(1);

[Brianna Selles]

syms x
y = piecewise(0<=x & x<=3, 4*x^1/3, 3<x & x<=6, pi^(x+2.71828183))
fplot(y,'c')

So this?

[Walter Roberson]

y = piecewise(0<=x & x<=3, 4*x^1/3, 3<x & x<=6, pi^(x+exp(1)))

Question: what is the value of the function for negative x or x > 6 ?

[Brianna Selles]

It is pi^x+e

[Brianna Selles]

I'm not quite sure, actually where you're getting that value from. I attatched a picture of the question.

[Walter Roberson]

No. Look carefully at the second equation. The x + e is all the same font size and is all raised higher than the pi. . If it were pi^x+e then it would have been

[Brianna Selles]

Yes!H ow do we raise e as an exponet?

[Brianna Selles]

syms x
e = exp(1)
y = piecewise(0<=x & x<=3, 4*x^1/3, 3<x & x<=6, pi^x^exp(1))
fplot(y,'c')

[Walter Roberson]

syms x
e = exp(1)
y = piecewise(0<=x & x<=3, 4*x^1/3, 3<x & x<=6, pi^(x+e))
fplot(y,'c')

[madhan ravi]

pi^(x+exp(1))

https://in.mathworks.com/help/matlab/ref/exp.html#bt9_gku-5

Answer 2

[madhan ravi]

You are almost there , change e to exp()

    syms x
    y = piecewise(0<=x<=3, 4*x^1/3, 3<x<=6, pi^(x+e)) % Note the parentheses around pi
    fplot(y,'c') % change this line
    doc fplot % to see more examples