Summing up values of A matrix if it matches the same value in B

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JL
JL am 27 Aug. 2019
Kommentiert: JL am 27 Aug. 2019
Hi everyone, I have 2 matrices A and B
A =[1;
2;
1;
3;
4;
5;
6;];
B = [40.5511;
40.5511;
34.6732;
34.6731;
32.1111;
32.1111;
32.1111;]
I want to create C by summing up the values in A if they have the same corresponding value in B.
C = [3 40.5511;
1 34.6732;
3 34.6731;
15 32.1111;];

Akzeptierte Antwort

Alex Mcaulley
Alex Mcaulley am 27 Aug. 2019
One option:
[G,ID] = findgroups(B);
C = [splitapply(@sum,A,G),ID]
C =
15.0000 32.1111
3.0000 34.6731
1.0000 34.6732
3.0000 40.5511
  4 Kommentare
Alex Mcaulley
Alex Mcaulley am 27 Aug. 2019
You can change the visualization of your command window using format. Do you mean this?
format short
C =
15.0000 32.1111
3.0000 34.6731
1.0000 34.6732
3.0000 40.5511
format long
C =
15.000000000000000 32.111100000000000
3.000000000000000 34.673099999999998
1.000000000000000 34.673200000000001
3.000000000000000 40.551099999999998

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