Switching an array of Vectors from Cartesian to Spherical Coordinates
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I have a 3 x 46 array called V which I am viewing as an array of 46 column vectors in Cartesian components, I am attempting to switch the components to spherical, so that I have an array of 46 column vectors in spherical polar coordinates r, theta, phi using the cart2sph function but I cannot seem to get the syntax right?
Do I need to separate out the rows first
X=V(1,:);
Y=V(2,:);
Z=V(3,:);
or can the function be applied directly to the array to make a conversion?
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Antworten (3)
dpb
am 25 Aug. 2019
Bearbeitet: dpb
am 25 Aug. 2019
The documentation syntax is pretty clear--
"[azimuth,elevation,r] = cart2sph(x,y,z) transforms corresponding elements of the Cartesian coordinate arrays x, y, and z to spherical coordinates azimuth, elevation, and r."
Yes, you must supply three separate x,y,z coordinate arrays to cart2sph because it can operate on either scalar, vector or array inputs and so the three coordinates have to be separated.
If you have the array, you don't need to create explicit temporaries, just pass the references...
[az,el,r]=cart2sph(V(1,:),V(2,:),V(3,:));
4 Kommentare
dpb
am 25 Aug. 2019
Well, it is what it is... :)
Altho, yes, it could have been different. But, there hasn't seemed to be any overall coherent interface design regimen established by TMW to try to create such consistency, unfortunately, and with the plethora of new toolboxes and data classes and the transitioning to named parameter/object-oriented interfaces from the classic procedural ones, it's only getting worse with time.
dpb
am 25 Aug. 2019
Bearbeitet: dpb
am 25 Aug. 2019
"I already tried cart2sph(X,Y,Z) and I got a 1x46 array when I am looking for a 3x46 array..."
Because you didn't provide anything except the default ans location for Matlab to return the three variables [az,el,r] so all you got back was az; el and r weren't returned because that syntax didn't ask for them.
David Hill
am 25 Aug. 2019
Bearbeitet: David Hill
am 25 Aug. 2019
[ax,el,r]=cart2sph(V(:,1),V(:,2),V(:,3));
V=[ax,el,r];
I believe the above should work for you.
4 Kommentare
Bruno Luong
am 25 Aug. 2019
Bearbeitet: Bruno Luong
am 25 Aug. 2019
Tom has xyz data ranged in 3-rows not 3-columns
Bruno Luong
am 25 Aug. 2019
Bearbeitet: Bruno Luong
am 25 Aug. 2019
OK since nobody care to give you the complete commands I'll
[az,el,r] = cart2sph(V(1,:),V(2,:),V(3,:));
S = [az; el; r]; % <- here is your 3 x 46 array of spherical coordinates
4 Kommentare
Bruno Luong
am 25 Aug. 2019
Waoh; you coudn't figure out where is the radial component from
S = [az; el; r]
It's a third row if you pay attention.
dpb
am 25 Aug. 2019
Bearbeitet: dpb
am 25 Aug. 2019
To repeat my first comment--
The documentation syntax is pretty clear--
"[azimuth,elevation,r] = cart2sph(x,y,z) transforms corresponding elements of the Cartesian coordinate arrays x, y, and z to spherical coordinates azimuth, elevation, and r."
Nothing says you can't build an output array in whatever form/order you want it, but as Bruno says, "pay attention" to the documentation--it 'splains it all explicitly and even gives examples.
What might be "easier" is all dependent upon what you are actually going to do with the result which we only have in some general use of the word plot but no specific type nor code to know anything about the specific syntax needed to do so.
The above syntax directly from cart2sph has already built such a set of row vectors; if you want to use them. There's no need to necessarily build an array again at all excepting that is the form you asked for in the original question so folks were simply trying to oblige.
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